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Make your own using our Graph Builder or upload your own files, images or videos. All our charts are user-submitted.
« Previous Will the LHC create a black hole? | Color Copier Utilization at the Office Next »
WTF?? Did I miss something here….??!?
Nope, you’re just stupid.
Shut up Stinkey Head! >:(
lol thanks mars. I still think the graph is done wrong. Or its just really hard to read…. Or I took an extra dose of retard pills today.
I think all three lol
Shouldn’t the axes be switched? Effect of vehicle speed on parking lot occupancy
How exactly do you propose that vehicle speed affects occupancy? It makes way more sense the way it already is.
No, this makes sense… inventive graph too… the fewer the cars in the lot, the faster you will go, and more likely you are to drive across lanes, as illustrated
Exactly! It makes perfect sense.
The only thing wrong with the graph is that it makes the assumption that left to right equals less to more occupancy, and that bottom to top equals slower to faster.
But that’s forgivable because that’s how one would expect it to go.
It’s probably just confusing people because the illustration of the car is driving in the opposite “direction” from what one would expect from a graph.
But there’s definitely nothing wrong with it. I like it.
Empty parking lots increase my speed by 15mph against my will.
What happened to 88 mph?
Great Scott!
Nice one!
Brilliant! I love it; very witty.
OMG! Do you go to the Target in my town?? This is a perfect graph for that parking lot!
Oh, geeze, my Target, too!
Oh my god! Parking lots in my area tend to be painted with white lines and arranged into lanes too!
Hey dingbat – I meant the speed increase thing, not the lines. Besides my Target’s lines are yellow.
And yes, namecalling makes me feel better.
clever
I’m not going to confess to driving like this. But the graph is great!
88mph can be reached but my flux capacitor is BUSTED.
These get better all the time, great job!
Now do one like that showing the parabola described by fresh snow on the parking lot, given the same speed =D